[libre-riscv-dev] [Bug 173] dynamic partitioned "shift"

bugzilla-daemon at libre-riscv.org bugzilla-daemon at libre-riscv.org
Thu Feb 13 19:08:40 GMT 2020


--- Comment #18 from Luke Kenneth Casson Leighton <lkcl at lkcl.net> ---
ahno, it's even simpler than that.  it's:

* start off with every gate-bit inverted
* next loop: front of list is not-inverted, rest of list is inverted
* repeat until only one item left.

i'll write a quick bit of python to print out the table.

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